MCQ Bank
Since a bounded linear operator T from the normed space X to normed space Y is defined and given as; \forall x\in D\left( T\right) \exists k>0, such that \left\Vert Tx\right\Vert \leq k\left\Vert x\right\Vert , then \ \left\Vert T\right\Vert =0\Longrightarrow
- A) k=0
- B) k<0
- C) x\in \{0\}
- D) T is a zero operator
Let $T:D\left( T\right) \rightarrow Y$ be a bounded linear operator from normed space $X$ to Banach space $Y$, and $\forall x\in \overline{D\left( T\right) }~\exists ~$a sequence $\left\{ x_{n}\right\} $ in $D(T)$ such that $x_{n}\rightarrow x,$then$~\left\Vert Tx_{m}-Tx_{n}\right\Vert \Longrightarrow $
- A) $\left\{ Tx_{n}\right\} $ converges in $\overline{R(T)}$
- B) $\left\{ Tx_{n}\right\} $ converges in $Y$
- C) $\left\{ Tx_{n}\right\} $ converges in $\overline{Y}$
- D) $\left\{ Tx_{n}\right\} ~$may not converges in $Y$
On a normed space X, for the identity operator $I:X\rightarrow X,\left\Vert I\right\Vert =\underset{\underset{x\neq 0}{x\in D\left( I\right) }}{\sup }% \frac{\left\Vert Ix\right\Vert }{\left\Vert x\right\Vert }=$__________.
- A) $\left\Vert kx\right\Vert ,k>0$
- B) $1$
- C) $0$
- D) $\left\Vert x\right\Vert $
If T:% %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion ^{2}\rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion ^{2} defined by T(x,y)=\left( y,-5x+4y\right) , then T^{-1}\left( -2,7\right) =_______
- A) (-3,-2)
- B) (-3,2)
- C) (3,-2)
- D) (3,2)
Let B\left( {X,Y} \right) be the set of all ……………operators from a normed space X to a normed space Y. If Y is a Banach space, then B\left( {X,Y} \right) is a Banach space.
- A) Linear
- B) Unbounded linear
- C) Bounded linear
- D) Non linear
If $T_{1}$ and $T_{2}$ are equal operators defined on a normed space $X$, then for any $x\in X,T_{1}x=T_{2}x\Longrightarrow $
- A) $T_{1}-T_{2}$ is a zero operator
- B) $T_{1}-T_{2}$ is not necessarily a zero operator
- C)
- D)
If the integral operator I:c\left[ 0,1\right] \rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion , on the space of all contnuous functions on \left[ 0,1\right] defined by f(x)=\int_{0}^{1}x\left( t\right) dt, is a linear functional, then % \left\vert f\left( x\right) \right\vert \leq
- A) 1
- B) \left\Vert x\right\Vert
- C) \underset{0\leq t\leq 1}{\max }\left\vert x\left( t\right) \right\vert
- D) \left\vert x\right\vert
On a normed space X, for the zero operator O:X\rightarrow X,\left\Vert O\right\Vert =\underset{\underset{x\neq 0}{x\in D\left( I\right) }}{\sup }% \frac{\left\Vert Ox\right\Vert }{\left\Vert x\right\Vert }=________
- A) 0
- B) 1
- C) \left\Vert x\right\Vert
- D) \left\Vert kx\right\Vert ,k>0
For a fixed $k=\left( k_{i}\right) _{i=1}^{\infty }\in l^{2},$ defining the linear functional $f:l^{2}\rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion $ as $f\left( x\right) =\sum_{i=1}^{\infty }x_{i}k_{i},~\forall \left( x_{i}\right) _{i=1}^{\infty }\in l^{2},$ then $\left\vert f\left( x\right) \right\vert \leq $
- A) $\left\vert x\right\vert \left\vert k\right\vert $
- B) $\left\vert f\right\vert \left\vert x\right\vert $
- C) $\left\Vert x\right\Vert \left\Vert k\right\Vert ~$
- D) $\left\Vert f\right\Vert \left\Vert k\right\Vert $
Since a bounded linear operator $T$ from the normed space $X$ to normed space $Y$ is defined and given as; $\forall x\in D\left( T\right) $ $\exists $ $k>0,$ such that $\left\Vert Tx\right\Vert \leq k\left\Vert x\right\Vert ,$ then $\ \left\Vert T\right\Vert =$__________.
- A) None of these
- B) both $\underset{\underset{\times \neq 0}{x\in D(T)}}{\sup }\frac{\left\Vert Tx\right\Vert }{\left\Vert x\right\Vert }$ and $\underset{\underset{% \left\Vert x\right\Vert =1}{x\in D(T)}}{\sup }\left\Vert Tx\right\Vert $
- C) $\underset{\underset{\left\Vert x\right\Vert =1}{x\in D(T)}}{\sup }% \left\Vert Tx\right\Vert $
- D) $\underset{\underset{\times \neq 0}{x\in D(T)}}{\sup }\frac{\left\Vert Tx\right\Vert }{\left\Vert x\right\Vert }$
A bounded linear operator $T$ from the normed space $X$ to normed space $Y$ is defined and given as; $\forall x\in D\left( T\right) $ $\exists $ $k>0,$ such that $\left\Vert Tx\right\Vert \leq k\left\Vert x\right\Vert.$If $D\left( T\right) =\{0\}, $ then $\left\Vert T\right\Vert =$
- A) $\infty $
- B) $k^{2}$
- C) $0$
- D) $\frac{1}{k}$
T is a linear operator . If ${T^{ - 1}}$ exists, it is a
- A) non linear operator.
- B) discontinuous operator.
- C) linear operator.
- D) Zero operator.
Let T:X\rightarrow Y be an invertible linear operator from X to Y, where \dim X,\dim Y<\infty , then
- A) \dim X>\dim Y
- B) \dim X<\dim Y
- C) \dim X=\dim Y
- D) \dim X=-\dim Y
Let $T:% %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion \rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion $ be defined by $T\left( x\right) =x^{2}$, then the restriction $T_{|A}$ is one-one on $A=$
- A) $\left( -\infty ,1\right) $
- B) $\left( -\infty ,0\right) $
- C) $\left( -1,\infty \right) $
- D) $\left( -\infty ,\infty \right) $
If $T:% %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion ^{2}\rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion ~$is defined by $T\left( x,y\right) =y-x,$ then $T^{-1}\left( 6\right) =\left\{ \left( t,t-6\right) :t\in %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion \right\} \Longrightarrow $
- A) $T$ is not one-one
- B) $T$ is one-one
- C)
- D)
Since a bounded linear operator $T$ from the normed space $X$ to normed space $Y$ is defined and given as; $\forall x\in D\left( T\right) $ $\exists $ $k>0,$ such that $\left\Vert Tx\right\Vert \leq k\left\Vert x\right\Vert ,$ then the maximum value of $k$ is__________.
- A) any arbitrary non negative real number
- B) not defined
- C) $\underset{\underset{X\neq 0}{x\in D(T)}}{\inf }\frac{\left\Vert Tx\right\Vert }{\left\Vert x\right\Vert }$
- D) $\underset{\underset{X\neq 0}{x\in D(T)}}{\sup }\frac{\left\Vert Tx\right\Vert }{\left\Vert x\right\Vert }$
If $T$ is a linear opertor on a finite dimensional normed space $X$ having basis $\left\{ e_{1},e_{2},\ldots ,e_{n}\right\} ,$then for any $x\in X$ $\exists ~\left\{ \alpha _{i}\right\} _{i=1}^{n},$ $x=\sum_{i=1}^{n}% \alpha _{i}e_{i},$ then $\left\Vert T\left( \sum_{i=1}^{n}\alpha _{i}e_{i}\right) \right\Vert $
- A) $\leq \sum_{i=1}^{n}\left\vert T\alpha _{i}\right\vert \left\Vert e_{i}\right\Vert $
- B) $\leq \sum_{i=1}^{n}\left\vert T\alpha _{i}\right\vert \left\Vert Te_{i}\right\Vert $
- C) $\leq T\left\Vert \sum_{i=1}^{n}\alpha _{i}e_{i}\right\Vert $
- D) $\leq \sum_{i=1}^{n}\left\vert \alpha _{i}\right\vert \left\Vert Te_{i}\right\Vert $
For a fixed $t\in \left[ 0,1\right] ,$ defining the linear functional on the class of all continous functions on $\left[ 0,1\right] ,$ $f:c\left[ 0,1% \right] \rightarrow %TCIMACRO{\U{211d} }% %BeginExpansion \mathbb{R} %EndExpansion $ as $f\left( x\right) =x\left( t\right) ,~\forall x\in c\left[ 0,1\right] ,$ then $\left\Vert f\right\Vert =$
- A) $\underset{t\in \left[ 0,1\right] }{\min }x\left( t\right) $
- B) $1$
- C) $0$
- D) $\underset{t\in \left[ 0,1\right] }{\max }x\left( t\right) $
For an element x belongs to an inner product space , \left\langle {x,x} \right\rangle = ......... if and only if x=0.
- A) 0
- B) infinity
- C) less than 0
- D) greater than 0
The following expression represents ……… inequality \frac{{|x - z|}}{{1 + |x - z|}} \leqslant \frac{{|x - y|}}{{1 + |x - y|}} + \frac{{|y - z|}}{{1 + |y - z|}}
- A) Rectangle inequality
- B) Triangular inequality
- C) Minkowski’s inequality
- D) Holder’s inequality