MCQ Bank
If $f(x)=2-\frac{1}{x^{2}},$then $\lim_{x\rightarrow \infty }f(x)= ----$
- A) 2
- B) 3
- C) 0
- D) 1
A function f is continuous at $x=c$, if
- A) $\lim _{x \to c }f(x)$ does not exist.
- B) $\lim _{x \to c }f(x)$ exists but does not equal $f(c).$
- C) $f(x)$ is not defined at $x=c.$
- D) $\lim _{x \to c }f(x)$ exists and equals $f(c).$
$Consider\,\,the\,\,function\,\,f(x) = \,e^x ;\,\,Find\,\,the\,\,range\,\,of\,\,f\,\,is\,\, - - - - - .$
- A) $[0,\infty )\,$
- B) $(0,\infty )\,$
- C) $none\,\,of\,\,these$
- D) $[ - 1,1]$
If a function $f$ is differentiable at $x=c,$ then $f$ is
- A) Never continuous at $x=c.$
- B) Always continuous at $x=c.$
- C) Sometimes continuous at $x=c.$
- D) Differentiability at $x=c$ does not imply continuity at $x=c.$
Which of the following best describes a removable discontinuity?
- A) A point where the limit does not exist due to infinity.
- B) A point where the function has a jump.
- C) A point where the limit exists but is not equal to the function’s value.
- D) A point where the function is continuous.
For the function $$f(x)=x\sin \frac{1}{ x},\quad x\ne0,$$ which statement is true
- A) $\lim_{x\rightarrow 0} f(x) = 1$.
- B) The function is not defined at $x=0$.
- C) $\lim_{x\rightarrow 1/\pi} f(x) = 0$.
- D) $\lim_{x\rightarrow 0} f(x) = 0$.
On the graph of a function, a removable discontinuity appears as:
- A) A continuous curve.
- B) A vertical asymptote.
- C) A hole in the graph.
- D) A jump discontinuity.
For the function $f(x)=x\sin \frac{1}{x},\ \ \ x\neq 0,$\ which statement is true
- A) $\lim_{x\rightarrow 0}f(x)=0\$
- B) $\lim_{x\rightarrow \frac{1}{x}}f(x)=0\$
- C) The function is not defined at $x=0$
- D) $\lim_{x\rightarrow 0}f(x)=1\$
Which of the following functions is always continuous on its domain?
- A) Piecewise functions.
- B) Polynomial functions.
- C) Step functions.
- D) Rational functions.
If $f(x)=3-\frac{1}{x^{2}},\ \$then \ $\lim_{x\rightarrow \infty }f(x)=\ \ ----$
- A) 1
- B) 3
- C) 0
- D) 2
For the function defined as $$f\left( x \right){\text{ }} = {\text{ }}cx,$$ for every $\epsilon > 0$ the formal definition ensures
- A) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,\,\,\,{\text{where}}\,\,\,0 < \delta < \epsilon.$
- B) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $0 < \delta < \epsilon/|c|.$
- C) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $-\epsilon < \delta < \epsilon.$
- D) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $0 < \delta < \epsilon.$
The value $1+$ $\lim_{x\rightarrow 0^{-}}\frac{\left\vert x\right\vert }{x}$
- A) 3
- B) 1
- C) 2
- D) 0
If $f(x)=2-\frac{1}{x^{2}},\ \$then \ $\lim_{x\rightarrow \infty }f(x)=\ \ ----$
- A) 0
- B) 3
- C) 1
- D) 2
If $\lim_{x\rightarrow 0}f(x)=20\$and $\lim_{x\rightarrow 0}g(x)=-5,$ then $\lim_{x\rightarrow 0}\frac{f(x)}{g(x)}$ is
- A) -4
- B) 0
- C) -5
- D) 20
For two functions f(x) and g(x), the composit function fog(x) is defined as -------
- A) f(g(x))
- B) g(f(x))
- C) None of these
- D) (f-g)(x)
Rolle's Theorem says, suppose that $f$ is continuous on the closed interval $[a,b]$ and differentiable on the open interval $(a,b)$ and $f(a) = f(b).$
- A) Then $f'(c)$ exists for some $c$ in the open interval $(a,b).$
- B) Then $f'(c) = 0$ for some $c$ in the open interval $(a,b).$
- C) Then $f'(c) = 0$ for some $c$ in the open interval $(a,\infty).$
- D) Then $f'(c) \neq 0$ for some $c$ in the open interval $(a,b).$
The function $h(x) = - {x^3}$ is
- A) increasing on $( - \infty ,\infty ).$
- B) decreasing on $( - \infty ,\infty ).$
- C) positive on $( - \infty ,\infty ).$
- D) is undefined on $( - \infty ,\infty ).$
The Mean Value Theorem says, suppose that $f$ is differentiable on $[a,b],$ $f'(a)\ne f'(b),$ and $\mu$ is between $f'(a)$ and $f'(b).$
- A) Then $f'(c)=\mu$ for some $c$ in $(a,b).$
- B) Then $f'(c)\neq\mu$ for some $c$ in $(a,b).$
- C) Then $f'(c)$ may be 0 or $\mu$ for some $c$ in $(a,b).$
- D) Then $f'(c)=0$ for some $c$ in $(a,b).$
Identify an unbounded function on $[0,1]$
- A) $f(x) =x^2+1$
- B) $h(x) = x^3$.
- C) $g(x) = \ln x$.
- D) $v(x) = \sin x$.
$Investigate\,\,the\,\,\lim it\,\,of\,\,\,\mathop {\lim }\limits_{x \to 0^ - } \,\,\left( {\frac{{\left| x \right|}}{x} + x} \right) = - - - - .$
- A) $0$
- B) $1$
- C) $none\,\,of\,\,these$
- D) $- 1$