MCQ Bank
If f (x) = x^2 is defined on the interval [-1, 3], then which of the following is true about it.
- A) Its relative maximum value is 9.
- B) None of these.
- C) Its absolute maximum value is 9.
- D) Its absolute maximum value is 0.
\[{\text{The integral }}\int {{{\sec }^2}(5{x^2})\,.10x\,dx\,} {\text{will be equal to ?}}\]
- A) \[\sec (5{x^2}).\tan (5{x^2}) + c\]
- B) \[\tan (5x) + c\]
- C) \[{\text{se}}{{\text{c}}^2}(10x) + c\]
- D) \[\tan (5{x^2}) + c\]
Sum of cubes of n-terms of a series whose nth term is ‘n’ = ---
- A) Square of n(n+1)/2
- B) Square of n(n+1)(2n+1)/6
- C) Square of (n+1)/2
- D) Square of n(n+1)/6
While using Newton’s mathod,which of the following will be the best initial approximate solution to solve the equation: x-Sinx=0
- A) x=pi/2
- B) x=-pi/2
- C) x=pi
- D) x=0
If x = (4^2) + (5^2) + (6^ 2) + . . . + (30^2), then x = ________.
- A) 465.
- B) 9455.
- C) 9441.
- D) 400.
Area of a rectangle whose width is 5 units and length is 6 units will be ….
- A) None of these
- B) 11 units
- C) 22 units
- D) 30 square units
What is the estimated area under f(x) = 9 - x2 from x = 0 to x = 4 with mid points for n = 1?
- A) 20
- B) 21
- C) 24
- D) 28
\[\text{If }{f}'(x)={{x}^{2}}-x\text{. Then the critical points of the function }f\text{ are}\]
- A) 0, 2
- B) 1, -1
- C) 1, 2
- D) 0, 1
For the area under the curve f(x) = x+2 from x = 2 to x = 4 with mid points approximations for n = 1, what will be the value of xk* ?
- A) 3
- B) 3.5
- C) 2
- D) 2.5
\[{\text{The integral }}\int {\frac{{10x}}{{{{(5{x^2} + 1)}^2}}}\,dx\,} {\text{will be equal to ?}}\]
- A) \[ - \frac{1}{{{{(5{x^2} + 1)}^3}}} + c\]
- B) \[ - \frac{1}{{5{x^2} + 1}} + c\]
- C) \[ - \frac{1}{{5x + 1}} + c\]
- D) \[\frac{1}{{5{x^2} + 1}} + c\]
$${\text{The integral }}\int {\frac{{4x}}{{{{(2{x^2} + 1)}^2}}}\,dx\,} {\text{will be equal to ?}}$$
- A) $$- \frac{1}{{{{(2{x^2} + 1)}^3}}} + c$$
- B) $$- \frac{1}{{2x + 1}} + c$$
- C) $$\frac{1}{{2{x^2} + 1}} + c$$
- D) $$- \frac{1}{{2{x^2} + 1}} + c$$
If ‘n’ goes from 1 to 3 and the summation of ‘na’ = definite integral of ‘1’ on closed interval [0,1], then the value of ‘a’=------------
- A) -6
- B) 1/6
- C) 6
- D) -1/6
$${\text{The integral }}\int {\sqrt {4x - 3} \,dx\,} {\text{will be equal to ?}}$$
- A) $$\frac{{{{(4x - 3)}^{\frac{3}{2}}}}}{6} + c$$
- B) $$\frac{{{{(4x + 3)}^{\frac{3}{2}}}}}{6} + c$$
- C) $${\text{None of these}}$$
- D) $$\frac{{{{(4x - 3)}^{\frac{3}{2}}}}}{3} + c$$
summation of (6) ;where ( j varies from 1 to 8) indicates to add ‘6’ to itself ……….. times.
- A) 8
- B) 11
- C) 9
- D) 10
\[\int {\tan x} dx = \_\_\_\_\_\_\_\_\_\_\_\_\_\_.\]
- A) \[{\sec ^2}x + C\]
- B) \[\ln \left| {\sec x} \right| + C\]
- C) \[\ln |\cos x| + C\]
- D) \[\ln \left| {\sin x} \right| + C\]
$$\int {\tan x} dx = \_\_\_\_\_\_\_\_\_\_\_\_\_\_.$$
- A) $$\ln \left| {\sin x} \right| + C$$
- B) $$\ln |\cos x| + C$$
- C) $${\sec ^2}x + C$$
- D) $$\ln \left| {\sec x} \right| + C$$
The approximate solution is possible to generate using Newton’s Method if ___________.
- A) the tangent line(at approximated points) must crosses the x - axis.
- B) the slope of tangent line(at any approximated point) is zero.
- C) None of these.
- D) the tangent line(at any approximated point) is parallel to x- axis.
If f(x) = x^5 + x, then which of the following is true about it.
- A) Its anti – derivative is 5x^4 + 1.
- B) Its anti – derivative is x^5/5 + 1.
- C) Its anti – derivative is x^6/6 + x^2/2 + 6.
- D) None of these.
If $f''(x) > 0\,\forall \,x \in I$, then the graph of $f$ is___________ on $I$.
- A) concave downward
- B) concave upward
- C) None of these
- D) constant
For the area under the curve f(x) = 2x from x = 0 to x = 12 with right points approximations for n = 3, what will be the values of xk* ?
- A) 6, 9 and 12
- B) 0, 6 and 12
- C) 2, 7 and 12
- D) 4, 8 and 12