MCQ Bank

Subjects
All Subjects 63 ACC311
F:210
210
ACC31Q
F:97
97
ACC501
F:248
248
BIF101
F:37
37
BIF401
F:27
27
BIF501
F:63
63
BIF602
F:3
3
BIF604
F:67
67
BIO101
F:17
17
BIO401
F:24
24
BIO503
F:48
48
BIO504T
F:12
12
BIO5101
F:25
25
BIO5105
F:18
18
BIO732
F:49
49
BNK601
F:129
129
BNK610
F:69
69
BNK611
F:102
102
BT101
F:80
80
BT102
F:53
53
BT201
F:246
246
BT301
F:30
30
BT302
F:35
35
BT401
F:163
163
BT402
F:37
37
BT403
F:43
43
BT404
M:9
9
BT405
F:41
41
BT406
F:106
106
BT501
F:141
141
BT503
F:74
74
BT504
F:67
67
BT505
F:68
68
BT511T
F:27
27
BT601
F:69
69
BT603
F:21
21
BT604
F:19
19
BT605
F:58
58
BT614T
F:37
37
CHE201
F:77
77
CS001
F:58
58
CS101
F:166
166
CS201
M:97 F:247
344
CS201P
F:200
200
CS202
F:192
192
CS204
F:77
77
CS205
F:87
87
CS206
F:57
57
CS301
F:141
141
CS301P
F:63
63
CS302
F:192
192
CS304
F:89
89
CS304P
F:147
147
CS306
F:75
75
CS311
F:132
132
CS312
F:47
47
CS314
F:84
84
CS315
F:57
57
CS401
F:117
117
CS402
M:67 F:140
207
CS403
F:162
162
CS403P
F:120
120
CS405
F:70
70
CS406
F:28
28
CS407
F:70
70
CS408
F:76
76
CS409
F:43
43
CS411
F:100
100
CS420
F:106
106
CS432
F:80
80
CS435
F:46
46
CS441
F:73
73
CS442
F:29
29
CS501
F:120
120
CS502
F:156
156
CS504
F:179
179
CS505
F:49
49
CS506
F:196
196
CS507
F:165
165
CS508
F:227
227
CS510
F:63
63
CS521
F:26
26
CS525
F:25
25
CS601
F:137
137
CS602
F:105
105
CS603
F:62
62
CS604
F:177
177
CS605
F:82
82
CS606
F:194
194
CS607
F:134
134
CS609
F:89
89
CS610
F:126
126
CS611
F:78
78
CS614
F:126
126
CS615
F:121
121
CS620
F:62
62
CS621
F:38
38
CS625
F:27
27
CS626
F:30
30
CS627
F:39
39
CS636
F:40
40
ECE302
F:21
21
ECO302
F:36
36
ECO303
F:20
20
ECO401
F:383
383
ECO402
F:99
99
ECO403
F:137
137
ECO404
F:129
129
ECO603
F:53
53
ECO606
F:108
108
ECO607
F:182
182
ECO609
F:48
48
ECO610
F:74
74
ECO613
F:50
50
ECO616
F:68
68
EDU101
F:72
72
EDU301
F:20
20
EDU302
F:57
57
EDU303
F:113
113
EDU304
F:33
33
EDU305
F:88
88
EDU401
F:117
117
EDU402
F:46
46
EDU403
F:37
37
EDU405
F:87
87
EDU406
F:75
75
EDU410
F:65
65
EDU411
F:312
312
EDU430
F:147
147
EDU431
F:62
62
EDU433
F:66
66
EDU501
F:42
42
EDU505
F:41
41
EDU510
F:15
15
EDU512
F:86
86
EDU515
F:12
12
EDU516
F:54
54
EDU601
F:129
129
EDU602
F:52
52
EDU604
F:103
103
EDU654
F:25
25
EDU705
F:26
26
EDUA430
F:77
77
ENG001
F:417
417
ENG101
F:344
344
ENG201
F:289
289
ENG301
F:340
340
ENG501
F:73
73
ENG502
F:55
55
ENG503
F:31
31
ENG504
F:44
44
ENG505
F:68
68
ENG506
F:60
60
ENG507
F:64
64
ENG508
F:61
61
ENG509
F:50
50
ENG510
F:41
41
ENG511
F:102
102
ENG512
F:44
44
ENG513
F:35
35
ENG514
F:57
57
ENG515
F:37
37
ENG516
F:50
50
ENG517
F:38
38
ENG518
F:65
65
ENG519
F:64
64
ENG520
F:40
40
ENG522
F:92
92
ENG523
F:76
76
ENG524
F:48
48
ENG529
F:34
34
ETH100
F:145
145
ETH201
F:20
20
FIN611
F:113
113
FIN621
F:168
168
FIN622
F:162
162
FIN623
F:203
203
FIN624
F:99
99
FIN625
F:96
96
FIN630
F:217
217
FIN702
F:56
56
GSC101
F:423
423
GSC201
F:47
47
HRM624
F:220
220
HRM627
F:300
300
ISL201
F:39
39
ISL202
F:903
903
IT430
F:280
280
IT601
F:31
31
IT602
F:33
33
MB502T
F:67
67
MCD403
F:20
20
MCD504
F:80
80
MCM101
F:98
98
MCM301
F:66
66
MCM304
F:52
52
MCM310
F:114
114
MCM311
F:96
96
MCM401
F:108
108
MCM411
F:76
76
MCM431
F:118
118
MCM501
F:105
105
MCM511
F:44
44
MCM514
F:21
21
MCM515
F:21
21
MCM516
F:55
55
MCM517
F:68
68
MCM520
F:67
67
MCM532
F:42
42
MCM601
F:99
99
MCM604
F:115
115
MCM610
F:85
85
MGMT611
F:205
205
MGMT623
F:160
160
MGMT625
F:126
126
MGMT627
F:130
130
MGMT628
F:234
234
MGMT629
F:99
99
MGMT630
F:112
112
MGT101
F:330
330
MGT111
F:197
197
MGT201
F:110
110
MGT211
F:175
175
MGT301
F:215
215
MGT401
F:30
30
MGT402
F:107
107
MGT404
F:135
135
MGT411
F:194
194
MGT501
F:396
396
MGT502
F:555
555
MGT503
F:325
325
MGT504
F:214
214
MGT510
F:561
561
MGT513
F:80
80
MGT520
F:231
231
MGT522
F:116
116
MGT601
F:121
121
MGT602
F:270
270
MGT603
F:330
330
MGT604
F:123
123
MGT605
F:66
66
MGT610
F:231
231
MGT611
F:122
122
MGT613
F:220
220
MGT713
F:44
44
MIC501T
F:40
40
MKT501
F:250
250
MKT530
F:71
71
MKT610
F:83
83
MKT621
F:94
94
MKT624
F:114
114
MKT630
F:127
127
MTH001
F:276
276
MTH100
F:216
216
MTH101
F:1292
1292
MTH102
F:32
32
MTH104
F:64
64
MTH201
F:68
68
MTH202
F:238
238
MTH301
F:406
406
MTH302
F:778
778
MTH303
F:160
160
MTH304
F:35
35
MTH401
F:226
226
MTH403
F:147
147
MTH404
F:41
41
MTH405
F:132
132
MTH501
F:366
366
MTH601
F:266
266
MTH603
F:160
160
MTH621
F:105
105
MTH622
F:62
62
MTH631
F:167
167
MTH632
F:97
97
MTH633
F:54
54
MTH634
F:67
67
MTH641
F:179
179
MTH642
F:76
76
MTH643
F:22
22
MTH645
F:63
63
MTH646
F:91
91
PAK301
F:155
155
PAK302
F:131
131
PAK522
F:51
51
PHY101
F:626
626
PHY301
F:95
95
PSC201
F:85
85
PSC401
F:48
48
PSY101
F:409
409
PSY401
F:166
166
PSY402
F:43
43
PSY403
F:262
262
PSY404
F:137
137
PSY405
F:174
174
PSY406
F:244
244
PSY407
F:175
175
PSY408
F:207
207
PSY409
F:143
143
PSY502
F:264
264
PSY504
F:126
126
PSY505
F:108
108
PSY511
F:69
69
PSY512
F:192
192
PSY513
F:175
175
PSY514
F:104
104
PSY515
F:140
140
PSY516
F:88
88
PSY610
F:81
81
PSY611
F:132
132
PSY631
F:116
116
PSY632
F:180
180
PSYP402
F:90
90
PSYP631
F:185
185
SE601
F:21
21
SE602
F:36
36
SOC101
F:1279
1279
SOC201
F:191
191
SOC301
F:63
63
SOC302
F:94
94
SOC401
F:143
143
SOC404
F:109
109
SOC609
F:82
82
SOC617
F:59
59
STA301
F:402
402
STA302
F:34
34
STA630
F:298
298
STA641
F:87
87
URD101
F:158
158
ZOO102
F:9
9
ZOO103
F:10
10
ZOO403
F:50
50
ZOO501
F:23
23
ZOO502
F:9
9
ZOO503
F:153
153
ZOO504
F:139
139
ZOO505
F:27
27
ZOO507
F:21
21
ZOO510
F:136
136
ZOO518T
F:20
20
ZOO519T
F:17
17
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BIF501 — PDF
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63 result(s)
BIF501 Final Term AI Solved
Q40

Which computational approach is used for the modified protein identification.

  • A) Dynamic Programming
  • B) Exhaustive search
  • C) Brute force
  • D) Divide and conquer
AI Explanation
Modified protein identification can require searching through possible peptide modifications and matching them against observed spectra. An exhaustive search systematically evaluates the possible modified forms to identify the best match.
BIF501 Final Term AI Solved
Q41

For aligning closely related sequence which alignment method is suitable.

  • A) Global Alignment
  • B) Multiple Sequence Alignment
  • C) Pairwise Alignment
  • D) Local Alignment
AI Explanation
Global alignment is suitable for closely related sequences of similar length because it aligns the sequences across their entire lengths. It is commonly implemented using the Needleman-Wunsch algorithm.
BIF501 Final Term AI Solved
Q42

If L = 3 and s = TATGGTGC, then spectrum (s, L) will be ______.

  • A) {TAT, ATG, TGG, GGT}
  • B) {TAT, ATG, TGG, GGT, ATG, GGT, TGC}
  • C) {TAT, ATG, TGG, GGT, GTG, TGC}
  • D) {TAT, ATG, TGG, GGT, GTG}
AI Explanation
For L = 3, the spectrum contains every consecutive substring of length three from TATGGTGC. These are TAT, ATG, TGG, GGT, GTG, and TGC, giving option C.
BIF501 Final Term AI Solved
Q43

The most frequent C-terminal ions of peptide are called _____.

  • A) a-ions
  • B) b-ions
  • C) y-ions
  • D) z-ions
AI Explanation
In peptide mass spectrometry, y-ions are the characteristic C-terminal fragment ions. They retain the C-terminal portion of the peptide after fragmentation.
BIF501 Final Term AI Solved
Q44

In Human Genome Project ______ nucleotide's were sequenced.

  • A) 4 Billion
  • B) 2 Billion
  • C) 3 Billion
  • D) 1 Billion
AI Explanation
The Human Genome Project determined the sequence of approximately 3 billion nucleotide bases in the human genome. This reference sequence provided a foundation for studying human genes and genomic variation.
BIF501 Final Term AI Solved
Q45

Glutamine (GLU) is most likely to found in _____.

  • A) Coils
  • B) Turns
  • C) Helices
  • D) Beta Sheets
AI Explanation
Glutamine (Gln) has a relatively high propensity to occur in alpha helices. Its polar amide side chain can participate in hydrogen bonding that supports helical structure.
BIF501 Final Term AI Solved
Q46

…….. Percent of Human genome has repeated elements

  • A) 50
  • B) 80
  • C) 30
  • D) 20
AI Explanation
Approximately 50% of the human genome consists of repeated or repetitive elements. These include transposable elements and other types of repetitive DNA sequences.
BIF501 Final Term AI Solved
Q47

Splicesome complex contain more than …………….. proteins

  • A) 500
  • B) 100
  • C) 200
  • D) 50
AI Explanation
The spliceosome is a large RNA-protein complex involved in pre-mRNA splicing. It contains more than 100 proteins along with small nuclear RNAs and associated components.
BIF501 Final Term AI Solved
Q48

________ size probes will be used to identify the fragments that are needs to be sequence in sequencing by hybridization process.

  • A) 8 – 32 nts
  • B) 32 – 60 nts
  • C) 100 – 500 nts
  • D) 2 – 8 nts
AI Explanation
Sequencing by hybridization uses short oligonucleotide probes to identify DNA fragments through complementary base pairing. Probes in the range of about 8–32 nucleotides are commonly used in this approach.
BIF501 Final Term AI Solved
Q49

_______ determines the protein structure.

  • A) Amino Acid
  • B) Nucleotides
  • C) DNA
  • D) RNA
AI Explanation
The amino acid sequence, or primary structure, is the fundamental determinant of a protein's three-dimensional structure. The sequence influences the folding and interactions that produce the final protein structure.
BIF501 Final Term AI Solved
Q50

Process of program cell death is also known as _______.

  • A) Necrosis
  • B) Restoration
  • C) Autophagic
  • D) Apoptosis
AI Explanation
Programmed cell death is called apoptosis. It is a regulated process that removes damaged or unnecessary cells in multicellular organisms.
BIF501 Final Term AI Solved
Q51

Which statement is true for protein sequencing technology?

  • A) Obtaining reads is difficult and assembly of those reads is easy
  • B) Obtaining reads is easy and assembly of those reads is difficult
  • C) Obtaining reads and their assembly both is difficult
  • D) Obtaining reads and their assembly both is easy
AI Explanation
Modern sequencing technologies can generate large numbers of sequence reads efficiently. The major computational challenge is assembling these short, overlapping reads into the correct complete sequence.
BIF501 Final Term AI Solved
Q52

The building block of protein is _________.

  • A) RNA
  • B) DNA
  • C) Amino Acids
  • D) Gene
AI Explanation
Amino acids are the basic building blocks of proteins. They are joined together by peptide bonds to form polypeptide chains.
BIF501 Final Term AI Solved
Q53

Bacterial Artificial Chromosomes fragment insert size is _______.

  • A) 25 kpb
  • B) 150 kb
  • C) 100 kpb
  • D) 50 kpb
AI Explanation
Bacterial Artificial Chromosomes (BACs) can accommodate relatively large DNA inserts, typically around 100–300 kb. A commonly cited BAC insert size is approximately 150 kb.
BIF501 Final Term AI Solved
Q54

ORFs within a single genomic sequence may overlap since there are ________ possible reading frames

  • A) 1
  • B) 6
  • C) 2
  • D) 3
AI Explanation
A double-stranded DNA sequence has six possible reading frames: three on each strand. ORFs can therefore overlap when they occur in different reading frames.
BIF501 Final Term AI Solved
Q55

Eukaryotic gene is called split gene because it is splitted into Exons and Introns

  • A) False
  • B) True
  • C)
  • D)
AI Explanation
Eukaryotic genes are called split genes because their coding regions (exons) are interrupted by non-coding introns. During RNA processing, introns are removed and exons are joined together.
BIF501 Final Term AI Solved
Q56

How many reading frames must be considered for a given double-stranded DNA sequence.

  • A) Three
  • B) Two
  • C) Six
  • D) Five
AI Explanation
A double-stranded DNA molecule has three possible reading frames on each strand. Therefore, a total of six reading frames must be considered.
BIF501 Final Term AI Solved
Q57

in Open Reading frames of a single genomic sequence ____ sequence are in forward direction whereas ___ sequence are in reverse direction.

  • A) 2,4
  • B) 4,2
  • C) 3,3
  • D) 5,1
AI Explanation
There are three possible reading frames in the forward direction and three in the reverse direction. Thus, a double-stranded DNA sequence has six possible reading frames in total.
BIF501 Final Term AI Solved
Q58

Which one is a start codon.

  • A) AUG
  • B) UAG
  • C) UAA
  • D) UGA
AI Explanation
AUG is the standard start codon and codes for methionine in the genetic code. UAG, UAA, and UGA are stop codons.
BIF501 Final Term AI Solved
Q59

of the human genome is so calledJunk DNA

  • A) 96-97%
  • B) 2-4%
  • C) 40%
  • D) 86.14%
AI Explanation
Only a small fraction of the human genome directly codes for proteins, while a much larger portion has historically been referred to as non-coding or 'junk' DNA. In the context of this question, the expected answer is approximately 96–97%.
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