MCQ Bank
$\begin{array}{l} The\,series\,\sum\limits_{}^{} {a_n b_n } \,\,\,converges\,\,if\,\,a_{n + 1} \le \,a_{n\,} \,for\,\,n\, \ge \,k,\,\,\mathop {\lim }\limits_{x \to \infty } \,\,a_n = 0,\,\,and\, \\\ |b_k + \,b_{k + 1} + ... + b_n | - - - - M,\,\,for\,\,some\,\,constant\,M. \\\ \end{array}$
- A) $\ge \,$
- B) $None\,of\,these$
- C) $\, \le$
- D) $<$
Generalized Mean Value Theorem says, If $f$ and $g$ are continuous on the closed interval $[a,b]$ and differentiable on the open interval $(a,b),$ then
- A) $$[g(b)-g(a)]=[f(b)-f(a)]g'(c)$$ for some $c$ in $(a,b).$
- B) $$[g(b)-g(a)]f'(c)=[f(b)-f(a)]g'(c)$$ for some $c$ in $(a,b).$
- C) $g'(x)=0$ for all $x$ in $(a,b)$.
- D) $g'(x)=f'(x)$ for all $x$ in $(a,b)$.
$$The\,\,\,function\,\,g\left( x \right) = x^2 \,\,is\, - - - - - \,on\,\,[0,\infty )\,.\,$$
- A) $$inrea\sin g$$
- B) $$decrea\sin g\,\,$$
- C)
- D)
If f(x) = |x| and g(x) = |5x – 2|. Then, fog =
- A) |f(x)|
- B) f(x)
- C) f^2(x)
- D) |g(x)|
$\begin{array}{l} If\,\,\,\sum\limits_{n = 1}^\infty {b_n } \,\,\,is\,\,rearrangement\,\,of\,\,an\,absolutely\,convergernt\,series \\\ \sum\limits_{n = 1}^\infty {a_n } ,\,\,then\,\,\sum\limits_{n = 1}^\infty {b_n } \,\,also\,\, - - - - - - \,\,absolutely,\,and\,\,to\,the\,\,same\,sum. \\\ \end{array}$
- A) $diverges$
- B) $converges$
- C)
- D)
The derivative of the function ${x^n}$ is
- A) $n{x^n}.$
- B) $n{x^{n - 1}}.$
- C) $\frac{n}{{{x^{n - 1}}}}.$
- D) ${x^{n - 1}}.$
The function $g(x) = {x^2}$ is
- A) having negative values on $[0,\infty ).$
- B) decreasing on $[0,\infty ).$
- C) increasing on $[0,\infty ).$
- D) undefined on $[0,\infty ).$
The value $1+$ $\lim_{x\rightarrow 0^{-}}\frac{\left\vert x\right\vert }{x}$
- A) 1
- B) 3
- C) 0
- D) 2
If $\lim_{x\rightarrow 0}f(x)=20\ $and $\lim_{x\rightarrow 0}g(x)=-5,$ then $\lim_{x\rightarrow 0}\frac{f(x)}{g(x)}$ is
- A) -4
- B) 0
- C) -5
- D) 20
For the function defined as \[f\left( x \right){\text{ }} = {\text{ }}cx,\] for every $\epsilon > 0$ the formal definition ensures
- A) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,\,\,\,{\text{where}}\,\,\,0 < \delta < \epsilon.$
- B) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $ -\epsilon < \delta < \epsilon.$
- C) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $0 < \delta < \epsilon/|c|.$
- D) $|f(x) - c{x_0}| < ,\qquad |x - {x_0}| < \delta ,$ where $0 < \delta < \epsilon.$
For the function $$f(x)=x\sin \frac{1}{ x},\quad x\ne0,$$ which statement is true
- A) $\lim_{x\rightarrow 0} f(x) = 0$.
- B) The function is not defined at $x=0$.
- C) $\lim_{x\rightarrow 0} f(x) = 1$.
- D) $\lim_{x\rightarrow 1/\pi} f(x) = 0$.
Which of the following functions is always continuous on its domain?
- A) Piecewise functions.
- B) Polynomial functions.
- C) Rational functions.
- D) Step functions.
If $f(x)=2-\frac{1}{x^{2}}, $then $\lim_{x\rightarrow \infty }f(x)= ----$
- A) 2
- B) 1
- C) 3
- D) 0
A function f is continuous at \(x=c\), if
- A) \(\lim _{x \to c }f(x)\) exists but does not equal \(f(c).\)
- B) \(f(x)\) is not defined at \(x=c.\)
- C) \(\lim _{x \to c }f(x)\) exists and equals \(f(c).\)
- D) \(\lim _{x \to c }f(x)\) does not exist.
For the function $f(x)=x\sin \frac{1}{x},\ \ \ x\neq 0,$\ which statement is true
- A) $\lim_{x\rightarrow 0}f(x)=0\ $
- B) $\lim_{x\rightarrow \frac{1}{x}}f(x)=0\ $
- C) The function is not defined at $x=0$
- D) $\lim_{x\rightarrow 0}f(x)=1\ $
Which of the following best describes a removable discontinuity?
- A) A point where the limit exists but is not equal to the function’s value.
- B) A point where the function has a jump.
- C) A point where the limit does not exist due to infinity.
- D) A point where the function is continuous.
$Consider\,\,the\,\,function\,\,f(x) = \,e^x ;\,\,Find\,\,the\,\,range\,\,of\,\,f\,\,is\,\, - - - - - .$
- A) $none\,\,of\,\,these$
- B) $[0,\infty )\,$
- C) $(0,\infty )\,$
- D) $[ - 1,1]$
If $f(x)=3-\frac{1}{x^{2}},\ \ $then \ $\lim_{x\rightarrow \infty }f(x)=\ \ ----$
- A) 1
- B) 0
- C) 2
- D) 3
For the function f(x)=x\sin \frac{1}{x},\ \ \ x\neq 0,\ which statement is true
- A) \lim_{x\rightarrow 0}f(x)=0\",\lim_{x\rightarrow 0}f(x)=1\"
- B) \lim_{x\rightarrow \frac{1}{x}}f(x)=0\",The function is not defined at x=0"
- C)
- D)
For the function f(x)=x\sin \frac{1}{ x},\quad x\ne0, which statement is true
- A) The function is not defined at x=0
- B) \lim_{x\rightarrow 0} f(x) = 0
- C) \lim_{x\rightarrow 1/\pi} f(x) = 0
- D) \lim_{x\rightarrow 0} f(x) = 1