MCQ Bank
How many subintervals of length ‘2’ will be formed for the interval [4,16] ?
- A) 4
- B) 6
- C) 5
- D) 7
Integral of x^2+x^3 is
NOTE: x^n means ‘x’ to the power ‘n’
- A) (1/3)x^4+(1/4)x^3 +C
- B) (1/4)x^4+(1/3)x^3 +C
- C) None of these
- D) x^3+x^4+C
What is the estimated area under f(x) = x from x = 0 to x = 3 with mid points for n = 3?
- A) 3.5
- B) 5.0
- C) 6.5
- D) 4.5
Let A be the area of a rectangle under a continuous function f(x) over a closed interval
[a, b]. If this area is divided in to ‘n’ sub-rectangles then width of each approximated sub-intervals is ---------
- A) (b-a)/n
- B) (a-b)/2
- C) (b-a)/2n
- D) (a-b)/n
Newton’s Method fails to find the approximate solution of an equation if _____________.
- A) the tangent line (at any approximated point) is not parallel to x-axis.
- B) None of these
- C) the tangent line(at any approximated point) is parallel to x-axis.
- D) the slope of the tangent line(at any approximated point) is non-zero
If x=-3 and x=3 are the two critical points of the function: f(x)=81x-3(x^3) then by using the 2nd derivative test, we can conclude that f(x) is relatively maximum at-----
- A) x= -9
- B) x=0
- C) x= 3
- D) x=-3
If the interval [3,7] is divided into ‘4’ equal subintervals ,then left endpoint of each subinterval will be………
- A) 4,5,6,7
- B) 5,6,7,8
- C) 3,4,5,6
- D) 3,6,8,9
For the area under the curve f(x) = x+2 from x = 2 to x = 8 with right end points approximations for n = 3, what will be the values of xk* ?
- A) 2, 5 and 8
- B) 2, 4 and 8
- C) 0, 4 and 8
- D) 4, 6 and 8
What is the summation of ‘kx’ where k goes from 1 to 30?
- A) 523x
- B) 419x
- C) 465x
- D) 414x
Which of the following is the sum of 2t^2 where t goes from 1 to 5?
- A) 2+8+28+32+50
- B) 2+18+32+50+62
- C) 2+18+28+32+60
- D) 2+8+18+32+50
By using Newton method, which of the following is the poorest initial approximate solution of equation:x+Cosx=0?
- A) x=0
- B) x=-pi/4
- C) x=pi/2
- D) x=-pi/3
Mean value theorem states that between any two points A and B on a curve y=f(x) , there must be at least one point where the Tangent line to the curve is……………joining A and B
- A) Perpendicular to the secant line
- B) Perpendicular to the tangent line
- C) Parallel to the tangent line
- D) Parallel to the secant line
If f(x)=1 / (x^2) and the interval is [-1,1] , then Rolle’s theorem can be applied.
- A) True
- B) False
- C)
- D)
\[{\text{The integral }}\int {{{\left( {{x^3} + 1} \right)}^{10}}\,.3{x^2}\,dx\,} {\text{will be equal to ?}}\]
- A) \[ - \frac{{{{\left( {{x^3} + 1} \right)}^{11}}}}{{11}} + c\]
- B) \[{\text{None of these}}\]
- C) \[\frac{{{{\left( {{x^3} + 1} \right)}^{11}}}}{{11}} + c\]
- D) \[\frac{{{{\left( {{x^3} - 1} \right)}^{11}}}}{{11}} + c\]
For the given function f(x)= 2(x^2)+1 in the interval [-1,2] , which condition of Rolle’s theorem is not satisfied.
- A) The function is differentiable in the interval
- B) The function is continuous in the interval
- C) None of these.
- D) f (-1) = f (2)
If ‘n’ goes from 1 to 3 and the summation of ‘na’ = derivative of Cosx at (pi/2), then the value of ‘a’=------
- A) -6
- B) 6
- C) 1/6
- D) -1/6
$${\text{The integral }}\int {\frac{{10x}}{{{{(5{x^2} + 1)}^2}}}\,dx\,} {\text{will be equal to ?}}$$
- A) $$\frac{1}{{5{x^2} + 1}} + c$$
- B) $$- \frac{1}{{{{(5{x^2} + 1)}^3}}} + c$$
- C) $$- \frac{1}{{5{x^2} + 1}} + c$$
- D) $$- \frac{1}{{5x + 1}} + c$$
\[{\text{The integral }}\int {\sqrt {2x + 3} \,dx} {\text{ will be equal to ?}}\]
- A) \[\frac{{{{\left( {2x + 3} \right)}^{\frac{1}{2}}}}}{3} + c\]
- B) \[\frac{{{{\left( {2x + 3} \right)}^{\frac{2}{3}}}}}{3} + c\]
- C) \[\frac{{{{\left( {2x + 3} \right)}^{\frac{3}{2}}}}}{2} + c\]
- D) \[\frac{{{{\left( {2x + 3} \right)}^{\frac{3}{2}}}}}{3} + c\]
\[\text{The vertical asymptotes of the function }f(x)=\frac{{{x}^{2}}-2x+1}{x(x-2)}\text{ are}\]
- A) 1, 2
- B) 0, 2
- C) 0, 1
- D) 1, -1
\[{\text{The integral }}\int {\sin (5x)dx} {\text{ will be equal to ?}}\]
- A) \[5\cos 5x + c\]
- B) \[{\text{ - }}\frac{{\cos 5x}}{5} + c\]
- C) \[\frac{{\cos 5x}}{5} + c\]
- D) \[{\text{ - }}\frac{{\cos 4x}}{5} + c\]