MCQ Bank
Richardson extrapolation method is used to improve the rate of convergence of a …………
- A) Series
- B) Sequence
- C)
- D)
Richardson extrapolation is method also known as …………
- A) Series acceleration method
- B) Sequence acceleration method
- C)
- D)
$\delta \,\, = \,\, - - - -$
- A) ${E^{\frac{1}{2}}}\,\, + \,\,\,{E^{ - \,\,\,\,\frac{1}{2}}}$
- B) $${E^{\frac{1}{2}}}\,\, - \,\,{E^{ - \,\,\,\,\frac{1}{2}}}$$
- C) $\frac{{{E^{\frac{1}{2}}}\,\, + \,\,\,{E^{ - \,\,\,\,\frac{1}{2}}}}}{2}$
- D) None
Zero-th order divided difference is defined as
- A) y[x0]=x0
- B) y[x0]=y1
- C) y[x0]=y0
- D) None of the given choices
In Composite Trapezoidal formula for integrating a Tabular function, we can approximate it with a polynomial whose ---------- order derivative vanishes.
- A) First
- B) Third
- C) Fourth
- D) Second
The step size “h” in numerical integration over the interval [a,b] is defined as
- A) h=(b/a)/n
- B) h=(a-b)/n
- C) h=(b+a)/n
- D) h=(b-a)/n
Geometrically the definite integral of any continuous function f(x) in the interval [a,b] gives ----------.
- A) Volume with dimensions f(x), ‘a’ and ‘b’
- B) Length of segment AB on real line
- C) Area of Trapezoid with dimension of ‘a’ and ‘b’
- D) Area under f(x) on [a,b]
: What will be the value of first order divided difference f[1,5]for the following data x:0 1 5 y:2 1 5
- A) 3
- B) 1
- C) 0
- D) 2
Which of the following method is simplest one to integrate numerically a given tabular function but give more error?
- A) Trapezoidal method
- B) Simpson’s 3/8 Rule
- C) Simpson’s 1/3 Rule
- D) Rectangular method
The double definite integral of a function is called…………
- A) None of the given choices
- B) Length of the curve
- C) Area under the curve
- D) Volume under the curve
$$For\,the\,given\,data\,{\text{points}}\,(4,2.2),\,(8,3.5),\,and\,(12,4.1)\,\,the\,divide\,difference\,table\,will\,be\,given\,as$$
- A) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 4&{2.2}&{0.325}&{} \\\ 8&{3.5}&{0.15}&{ - 0.0108} \\\ {12}&{4.1}&{}&{} \end{array}$$
- B) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 4&{2.2}&{0.325}&{} \\\ 8&{3.5}&{0.15}&{ - 0.0219} \\\ {12}&{4.1}&{}&{} \end{array}$$
- C) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 4&{2.2}&{0.325}&{} \\\ 8&{3.5}&{0.15}&{ - 0.098} \\\ {12}&{4.1}&{}&{} \end{array}$$
- D) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 4&{2.2}&{0.325}&{} \\\ 8&{3.5}&{0.15}&{ - 0.065} \\\ {12}&{4.1}&{}&{} \end{array}$$
$$\begin{gathered} What\,will\,be\,the\,value\,of\,'a'\,in\,the\,given\,divide\,difference\,table? \hfill \\\ \begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D}&{3rdD.D} \\\\ 2&{0.5}&{0.3}&a&{} \\\\ 4&{1.1}&{0.3}&{ - 0.0125}&{ - 0.0021} \\\\ 6&{1.7}&{0.25}&{}&{} \\\\ 8&{2..2}&{}&{}&{} \end{array} \hfill \\\\ \end{gathered}$$
- A) 0.0893
- B) 0
- C) 0.0612
- D) 0.0115
$$\begin{gathered} What\,will\,be\,the\,value\,of\,'a'\,in\,the\,given\,divide\,difference\,table? \hfill \\ \begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D}&{3rdD.D} \\\ 1&{0.4}&{0.25}&{0.0375}&{ - 0.0104} \\\ 3&{0.9}&{0.4}&a&{} \\\ 5&{1.7}&{0.3}&{}&{} \\\ 7&{2.3}&{}&{}&{} \end{array} \hfill \\\ \end{gathered}$$
- A) -0.0012
- B) -0.025
- C) -0.0343
- D) -0.0109
----------- difference is a symmetric function of its arguments.
- A) Backward
- B) None
- C) Forward
- D) Divided
$$For\,the\,given\,data\,{\text{points}}\,(2,0.3),\,(4,1),\,and\,(6,1.2)\,\,the\,divide\,difference\,table\,will\,be\,given\,as$$
- A) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 2&{0.3}&{0.1}&{} \\\ 4&1&{ - 0.0625}&{0.35} \\\ 6&{1.2}&{}&{} \end{array}$$
- B) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 2&{0.3}&{ - 0.0625}&{} \\\ 4&1&{0.1}&{0.35} \\\ 6&{1.2}&{}&{} \end{array}$$
- C) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 2&{0.3}&{0.35}&{} \\\ 4&1&{0.1}&{ - 0.0625} \\\ 6&{1.2}&{}&{} \end{array}$$
- D) $$\begin{array}{*{20}{c}} x&y&{1stD.D}&{2ndD.D} \\\ 2&{0.3}&{ - 0.0625}&{} \\\ 4&1&{0.35}&{0.1} \\\ 6&{1.2}&{}&{} \end{array}$$
At which of the following point the derivatives or slopes the functions f(x) = x – 2 and g(x) = x + 2 may differ?
- A) does not differ for any value of ‘x’
- B) x = -2
- C) x = 2
- D) differ for every value of ‘x’
The percentage error in numerical integration is defined as
- A) = (Theoretical Value-Experiment Value)/ Experiment Value*100
- B) = (Theoretical Value-Experiment Value)* Experiment Value*100
- C) = (Theoretical Value +Experiment Value)/ Experiment Value*100
- D) = (Theoretical Value-Experiment Value)/ Theoretical Value *100
We prefer ………over the Lagrange’s interpolating method for economy of computation.
- A) Newton’s forward difference method
- B) Newton’s backward difference method
- C) Newton’s divided difference method
- D) None of the given choices
Which of the following reason(s) lead towards the numerical integration methods?
- A) All above choices are true
- B) Analytical evaluation of integral is very complicated
- C) Analytical evaluation of integral is impossible
- D) Integrand is given in tabular form
Which of the following is the Richardson’s Extrapolation limit: F3(h/8) provided that F2(h/8) = F2(h/4) = 1 ?
- A) 63
- B) -1
- C) 64
- D) 1