MCQ Bank

Subjects
All Subjects 63 ACC311
F:210
210
ACC31Q
F:97
97
ACC501
F:248
248
BIF101
F:37
37
BIF401
F:27
27
BIF501
F:63
63
BIF602
F:3
3
BIF604
F:67
67
BIO101
F:17
17
BIO401
F:24
24
BIO503
F:48
48
BIO504T
F:12
12
BIO5101
F:25
25
BIO5105
F:18
18
BIO732
F:49
49
BNK601
F:129
129
BNK610
F:69
69
BNK611
F:102
102
BT101
F:80
80
BT102
F:53
53
BT201
F:246
246
BT301
F:30
30
BT302
F:35
35
BT401
F:163
163
BT402
F:37
37
BT403
F:43
43
BT404
M:9
9
BT405
F:41
41
BT406
F:106
106
BT501
F:141
141
BT503
F:74
74
BT504
F:67
67
BT505
F:68
68
BT511T
F:27
27
BT601
F:69
69
BT603
F:21
21
BT604
F:19
19
BT605
F:58
58
BT614T
F:37
37
CHE201
F:77
77
CS001
F:58
58
CS101
F:166
166
CS201
M:97 F:247
344
CS201P
F:200
200
CS202
F:192
192
CS204
F:77
77
CS205
F:87
87
CS206
F:57
57
CS301
F:141
141
CS301P
F:63
63
CS302
F:192
192
CS304
F:89
89
CS304P
F:147
147
CS306
F:75
75
CS311
F:132
132
CS312
F:47
47
CS314
F:84
84
CS315
F:57
57
CS401
F:117
117
CS402
M:67 F:140
207
CS403
F:162
162
CS403P
F:120
120
CS405
F:70
70
CS406
F:28
28
CS407
F:70
70
CS408
F:76
76
CS409
F:43
43
CS411
F:100
100
CS420
F:106
106
CS432
F:80
80
CS435
F:46
46
CS441
F:73
73
CS442
F:29
29
CS501
F:120
120
CS502
F:156
156
CS504
F:179
179
CS505
F:49
49
CS506
F:196
196
CS507
F:165
165
CS508
F:227
227
CS510
F:63
63
CS521
F:26
26
CS525
F:25
25
CS601
F:137
137
CS602
F:105
105
CS603
F:62
62
CS604
F:177
177
CS605
F:82
82
CS606
F:194
194
CS607
F:134
134
CS609
F:89
89
CS610
F:126
126
CS611
F:78
78
CS614
F:126
126
CS615
F:121
121
CS620
F:62
62
CS621
F:38
38
CS625
F:27
27
CS626
F:30
30
CS627
F:39
39
CS636
F:40
40
ECE302
F:21
21
ECO302
F:36
36
ECO303
F:20
20
ECO401
F:383
383
ECO402
F:99
99
ECO403
F:137
137
ECO404
F:129
129
ECO603
F:53
53
ECO606
F:108
108
ECO607
F:182
182
ECO609
F:48
48
ECO610
F:74
74
ECO613
F:50
50
ECO616
F:68
68
EDU101
F:72
72
EDU301
F:20
20
EDU302
F:57
57
EDU303
F:113
113
EDU304
F:33
33
EDU305
F:88
88
EDU401
F:117
117
EDU402
F:46
46
EDU403
F:37
37
EDU405
F:87
87
EDU406
F:75
75
EDU410
F:65
65
EDU411
F:312
312
EDU430
F:147
147
EDU431
F:62
62
EDU433
F:66
66
EDU501
F:42
42
EDU505
F:41
41
EDU510
F:15
15
EDU512
F:86
86
EDU515
F:12
12
EDU516
F:54
54
EDU601
F:129
129
EDU602
F:52
52
EDU604
F:103
103
EDU654
F:25
25
EDU705
F:26
26
EDUA430
F:77
77
ENG001
F:417
417
ENG101
F:344
344
ENG201
F:289
289
ENG301
F:340
340
ENG501
F:73
73
ENG502
F:55
55
ENG503
F:31
31
ENG504
F:44
44
ENG505
F:68
68
ENG506
F:60
60
ENG507
F:64
64
ENG508
F:61
61
ENG509
F:50
50
ENG510
F:41
41
ENG511
F:102
102
ENG512
F:44
44
ENG513
F:35
35
ENG514
F:57
57
ENG515
F:37
37
ENG516
F:50
50
ENG517
F:38
38
ENG518
F:65
65
ENG519
F:64
64
ENG520
F:40
40
ENG522
F:92
92
ENG523
F:76
76
ENG524
F:48
48
ENG529
F:34
34
ETH100
F:145
145
ETH201
F:20
20
FIN611
F:113
113
FIN621
F:168
168
FIN622
F:162
162
FIN623
F:203
203
FIN624
F:99
99
FIN625
F:96
96
FIN630
F:217
217
FIN702
F:56
56
GSC101
F:423
423
GSC201
F:47
47
HRM624
F:220
220
HRM627
F:300
300
ISL201
F:39
39
ISL202
F:903
903
IT430
F:280
280
IT601
F:31
31
IT602
F:33
33
MB502T
F:67
67
MCD403
F:20
20
MCD504
F:80
80
MCM101
F:98
98
MCM301
F:66
66
MCM304
F:52
52
MCM310
F:114
114
MCM311
F:96
96
MCM401
F:108
108
MCM411
F:76
76
MCM431
F:118
118
MCM501
F:105
105
MCM511
F:44
44
MCM514
F:21
21
MCM515
F:21
21
MCM516
F:55
55
MCM517
F:68
68
MCM520
F:67
67
MCM532
F:42
42
MCM601
F:99
99
MCM604
F:115
115
MCM610
F:85
85
MGMT611
F:205
205
MGMT623
F:160
160
MGMT625
F:126
126
MGMT627
F:130
130
MGMT628
F:234
234
MGMT629
F:99
99
MGMT630
F:112
112
MGT101
F:330
330
MGT111
F:197
197
MGT201
F:110
110
MGT211
F:175
175
MGT301
F:215
215
MGT401
F:30
30
MGT402
F:107
107
MGT404
F:135
135
MGT411
F:194
194
MGT501
F:396
396
MGT502
F:555
555
MGT503
F:325
325
MGT504
F:214
214
MGT510
F:561
561
MGT513
F:80
80
MGT520
F:231
231
MGT522
F:116
116
MGT601
F:121
121
MGT602
F:270
270
MGT603
F:330
330
MGT604
F:123
123
MGT605
F:66
66
MGT610
F:231
231
MGT611
F:122
122
MGT613
F:220
220
MGT713
F:44
44
MIC501T
F:40
40
MKT501
F:250
250
MKT530
F:71
71
MKT610
F:83
83
MKT621
F:94
94
MKT624
F:114
114
MKT630
F:127
127
MTH001
F:276
276
MTH100
F:216
216
MTH101
F:1292
1292
MTH102
F:32
32
MTH104
F:64
64
MTH201
F:68
68
MTH202
F:238
238
MTH301
F:406
406
MTH302
F:778
778
MTH303
F:160
160
MTH304
F:35
35
MTH401
F:226
226
MTH403
F:147
147
MTH404
F:41
41
MTH405
F:132
132
MTH501
F:366
366
MTH601
F:266
266
MTH603
F:160
160
MTH621
F:105
105
MTH622
F:62
62
MTH631
F:167
167
MTH632
F:97
97
MTH633
F:54
54
MTH634
F:67
67
MTH641
F:179
179
MTH642
F:76
76
MTH643
F:22
22
MTH645
F:63
63
MTH646
F:91
91
PAK301
F:155
155
PAK302
F:131
131
PAK522
F:51
51
PHY101
F:626
626
PHY301
F:95
95
PSC201
F:85
85
PSC401
F:48
48
PSY101
F:409
409
PSY401
F:166
166
PSY402
F:43
43
PSY403
F:262
262
PSY404
F:137
137
PSY405
F:174
174
PSY406
F:244
244
PSY407
F:175
175
PSY408
F:207
207
PSY409
F:143
143
PSY502
F:264
264
PSY504
F:126
126
PSY505
F:108
108
PSY511
F:69
69
PSY512
F:192
192
PSY513
F:175
175
PSY514
F:104
104
PSY515
F:140
140
PSY516
F:88
88
PSY610
F:81
81
PSY611
F:132
132
PSY631
F:116
116
PSY632
F:180
180
PSYP402
F:90
90
PSYP631
F:185
185
SE601
F:21
21
SE602
F:36
36
SOC101
F:1279
1279
SOC201
F:191
191
SOC301
F:63
63
SOC302
F:94
94
SOC401
F:143
143
SOC404
F:109
109
SOC609
F:82
82
SOC617
F:59
59
STA301
F:402
402
STA302
F:34
34
STA630
F:298
298
STA641
F:87
87
URD101
F:158
158
ZOO102
F:9
9
ZOO103
F:10
10
ZOO403
F:50
50
ZOO501
F:23
23
ZOO502
F:9
9
ZOO503
F:153
153
ZOO504
F:139
139
ZOO505
F:27
27
ZOO507
F:21
21
ZOO510
F:136
136
ZOO518T
F:20
20
ZOO519T
F:17
17
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BIF501 — PDF
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63 result(s)
BIF501 Final Term AI Solved
Q20

The mass of water H2O is ________.

  • A) 16 Daltons
  • B) 18 Daltons
  • C) 10 Daltons
  • D) 17 Daltons
AI Explanation
A water molecule (H2O) consists of two hydrogen atoms and one oxygen atom. Its molecular mass is approximately 2(1) + 16 = 18 Daltons.
BIF501 Final Term AI Solved
Q21

In shortgun sequencing technique the genome fragment length is ____.

  • A) 500 - 700
  • B) 1000 or above
  • C) 800 - 1000
  • D) 200 - 400
AI Explanation
In the described shotgun sequencing approach, genomic DNA is fragmented into relatively small pieces suitable for sequencing and assembly. A commonly cited fragment size range is approximately 500–700 base pairs.
BIF501 Final Term AI Solved
Q22

Mass spectrophotometer is used for the removal of …………………

  • A) Protein
  • B) Ions
  • C) Fragments
  • D) None of the above
AI Explanation
A mass spectrometer measures ions according to their mass-to-charge ratio. The ionisation and analysis process allows molecular fragments to be detected and characterised based on their mass-to-charge values.
BIF501 Final Term AI Solved
Q23

Sanger used _____ to digest insulin protein.

  • A) Protease enzyme
  • B) Restriction enzyme
  • C) Sonication
  • D) Nuclease enzyme
AI Explanation
Sanger used proteolytic enzymes to digest insulin into smaller peptide fragments for sequencing. Proteases cleave peptide bonds, producing fragments that can then be analysed to determine the protein sequence.
BIF501 Final Term AI Solved
Q24

Which of the following is incorrect regarding Ab Initio–Based Methods?

  • A) This type of method predicts the secondary structure based on a single query sequence
  • B) It measures the relative propensity of each amino acid belonging to a certain secondary structure element
  • C) The propensity scores are derived from known crystal structures
  • D) This type of method predicts the secondary structure based on a multiple query sequence
AI Explanation
Ab initio methods predict secondary structure from a single amino-acid sequence without requiring homologous sequences. Methods based on multiple query sequences are generally classified as homology or comparative approaches, making this statement incorrect.
BIF501 Final Term AI Solved
Q25

Most fragment assembly algorithm consists of the ______ steps.

  • A) Overlap and Layout
  • B) Overlap, Layout and Consensus
  • C) Layout and Consensus
  • D) Overlap and Consensus
AI Explanation
Most fragment assembly algorithms follow three main stages: determining overlaps between fragments, arranging them into a layout, and deriving a consensus sequence. These steps together reconstruct the original genome sequence.
BIF501 Final Term AI Solved
Q26

If several alanine’s found in the sequence, then it anticipates that a ______ secondary structure may be formed by them.

  • A) Loops
  • B) Coils
  • C) Alpha Helices
  • D) Beta Sheets
AI Explanation
Alanine has a high propensity to occur in alpha helices. Therefore, several alanine residues in a sequence can indicate a tendency for an alpha-helical secondary structure.
BIF501 Final Term AI Solved
Q27

Which amino acid form disulphide bridge

  • A) Glutamine
  • B) Proline
  • C) Alanine
  • D) Cysteine
AI Explanation
Cysteine residues can form disulphide bridges when the sulfur-containing side chains of two cysteines are oxidised. These covalent bonds help stabilise protein structure.
BIF501 Final Term AI Solved
Q28

Tyrosine (Tyr) is most likely to found in ______.

  • A) Turns
  • B) Helices
  • C) Coils
  • D) Beta Sheets
AI Explanation
Tyrosine has a relatively high propensity to occur in beta-sheet structures. Its aromatic side chain can participate in hydrophobic interactions that contribute to protein structure.
BIF501 Final Term AI Solved
Q29

The mass of ammonia is NH3 _______.

  • A) 18 Daltons
  • B) 16 Daltons
  • C) 19 Daltons
  • D) 17 Daltons
AI Explanation
Ammonia (NH3) contains one nitrogen atom with an atomic mass of about 14 Daltons and three hydrogen atoms totalling about 3 Daltons. Thus, its molecular mass is approximately 17 Daltons.
BIF501 Final Term AI Solved
Q30

The first step is to predict secondary structure from …………..

  • A) RNA
  • B) Primary
  • C) DNA
  • D) None of the above
AI Explanation
Protein secondary structure is predicted from the primary amino acid sequence. The primary sequence determines the local structural tendencies that lead to structures such as alpha helices and beta sheets.
BIF501 Final Term AI Solved
Q31

Alu fragment is ……………… bp long repeated fragment

  • A) 800
  • B) 300
  • C) 500
  • D) 400
AI Explanation
An Alu element is a short interspersed nuclear element (SINE) of approximately 300 base pairs in length. Alu sequences are highly repeated throughout the human genome.
BIF501 Final Term AI Solved
Q32

which algorithm is used for finding the shortest superstring of a substring/read of genome?

  • A) Superstring Problem Algorithm
  • B) Shortest Superstring Problem Algorithm
  • C) String finding Algorithm
  • D) Shortest read Algorithm
AI Explanation
The Shortest Superstring Problem addresses how to reconstruct a shortest sequence containing all given reads or substrings. It is relevant to genome assembly because overlapping sequencing reads can be combined into a larger sequence.
BIF501 Final Term AI Solved
Q33

In smith and waterman algorithm the initial matrix is created with _____ columns and _____ rows.

  • A) M+1 and N+1
  • B) M+1 and N
  • C) M and N+1
  • D) M and N
AI Explanation
The Smith-Waterman dynamic programming matrix includes an initial row and column for the empty prefixes of the two sequences. Therefore, for sequences of lengths M and N, the matrix has M+1 columns and N+1 rows.
BIF501 Final Term AI Solved
Q34

Which of the following is un true regarding Chou–Fasman methods?

  • A) First-generation method
  • B) Developed in the 1970s,
  • C) Suffer from the fact that the prediction rules are somewhat arbitrary
  • D) Based on single sequence statistics with clear relation to known protein-folding theories
AI Explanation
The Chou-Fasman method is a first-generation prediction method developed in the 1970s and is based largely on statistical propensities from known protein structures. It does not have a clear direct relationship to established protein-folding theories, making this statement untrue.
BIF501 Final Term AI Solved
Q35

The most frequent N-terminal ions of peptide are called _____.

  • A) b-ions
  • B) y-ions
  • C) a-ions
  • D) z-ions
AI Explanation
In peptide mass spectrometry, b-ions are the characteristic N-terminal fragment ions. They retain the N-terminal portion of the peptide after fragmentation.
BIF501 Final Term AI Solved
Q36

Find the lexicographic order of {TAT, ATG, TGG, GGT, GTG, TGC}.

  • A) TAT, TGC, TGG, GTG, GGT, ATG
  • B) ATG, GTG, TAT, GGT, TGC, TGG
  • C) ATG, GGT, GTG, TAT, TGC, TGG
  • D) TGG, TGC, TAT, GTG, GGT, ATG
AI Explanation
Lexicographic ordering arranges strings according to alphabetical order of their characters. Using A < G < T, the sequences sort as ATG, GGT, GTG, TAT, TGC, TGG.
BIF501 Final Term AI Solved
Q37

The first step of Needleman-wunsch algorithm is to ______.

  • A) Matrix filling with the appropriate scores
  • B) Traceback the sequences for a suitable alignment
  • C) Initialization of matrix with gap penalty
  • D) Initialization of a matrix with zero’s
AI Explanation
The Needleman-Wunsch algorithm begins by initializing the dynamic programming matrix, including the first row and column with cumulative gap penalties. The matrix is then filled with alignment scores followed by traceback.
BIF501 Final Term AI Solved
Q38

Steps of mass spectrometry involves ______.

  • A) Protein --> Peptide --> small fragmentation --> measure mass
  • B) Peptide --> small fragmentation --> measure mass
  • C) Protein --> small fragmentation --> measure mass
  • D) Small fragmentation --> Peptide --> Proteins --> measure mass
AI Explanation
In mass spectrometry-based peptide sequencing, a peptide is fragmented into smaller ions and their mass-to-charge ratios are measured. These fragment masses provide information about the peptide sequence.
BIF501 Final Term AI Solved
Q39

BAC stands for …………………..

  • A) None of the above
  • B) Bacterial artifact chromosome
  • C) Blood alcohol concentration
  • D) Bacterial artificial chromosome
AI Explanation
BAC stands for Bacterial Artificial Chromosome. BACs are cloning vectors derived from bacterial plasmids and are used to maintain relatively large DNA fragments.
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