MCQ Bank
The\,point\,( - \,42,\,\,{35^0}\,\,)\,\,{\text{and the point - - - - - - - - - - - - - - }}\,{\text{are the same in polar system}}{\text{.}}
- A) (\,42,\,\,{215^0}\,)
- B) (122,\,\,{35^0}\,\,)
- C) (\,122,\,\,{215^0}\,\,)
- D) (\,\,42,\,\,{35^0}\,\,)
{\text{Reversing the order of integration}} \int\limits_0^1 {\int\limits_{4x}^4 {{e^{ - {y^2}}}dydx = } }
- A) \int\limits_0^4 {\int\limits_0^{\frac{y}{2}} {{e^{ - {y^2}}}dx} } dy
- B) \int\limits_0^4 {\int\limits_0^{3y} {{e^{ - {y^2}}}dx} } dy
- C) \int\limits_0^4 {\int\limits_0^{\frac{y}{4}} {{e^{ - {y^2}}}dx} } dy
- D) \int\limits_0^4 {\int\limits_0^{2y} {{e^{ - {y^2}}}dx} } dy
{\text{The}} \int\limits_0^1 {{e^{{y^2}}}dx} =
- A) e - 1
- B) {e^{{y^2}}}
- C) 0
- D) e + 1
Can we evaluate the following integral in given order of integration \[{\kern 1pt} \int\limits_0^{\frac{1}{2}} {\int\limits_{2x}^1 {{e^{{y^2}}}} } dydx\]
- A) Yes
- B) No
- C)
- D)
\[{\text{The}}\,\,{\text{equation,}}\,\,\,{r^2} = 4\cos 2\theta ,\,\,{\text{represents}}\,\,{\text{a}}\,\,\_\_\_\_\_\_\_\_\_.\]
- A) \[{\text{lemniscate}}\]
- B) \[{\text{spiral}}\]
- C) \[{\text{cardioids}}\]
- D) \[{\text{rose }}\,\,{\text{curve}}\]
\eqalign{ & {\text{Polar co - ordinates of a point are}} \left( {{\text{ - 3,}} \frac{{ - 3\pi }}{4}} \right){\text{. Which of the following is another possible polar }} \cr & {\text{co - ordinates representation of this point?}} \cr}
- A) \left( {{\text{ - 3,}} \frac{\pi }{2}} \right)
- B) \left( {{\text{ - 3,}} \frac{\pi }{3}} \right)
- C) \left( {{\text{ - 3,}} \frac{{3\pi }}{4}} \right)
- D) \left( {{\text{ - 3,}} \frac{\pi }{4}} \right)
\[ {\text{After}}\,{\text{reversing the order of limits of }}\,\int\limits_0^2 {\int\limits_x^2 {f(x,\,y)\,dy\,dx} } ,\,{\text{we}}\,{\text{get}}\, - - - - - - \]
- A) \[ \int\limits_y^2 {\int\limits_x^2 {f(x,\,y)\,dx\,dy} } \]
- B) \[ \int\limits_x^2 {\int\limits_0^y {f(x,\,y)\,dy\,dx} } \]
- C) \[ \int\limits_0^2 {\int\limits_0^y {f(x,\,y)\,dx\,dy} } \]
- D) \[ \int\limits_0^2 {\int\limits_x^2 {f(x,\,y)\,dx\,dy} } \]
\[\begin{gathered} {\text{If}}\,\,a > 0,\,\,{\text{then}}\,\,{\text{equations}}\,\,{\text{of}}\,\,{\text{the}}\,\,{\text{form:}} \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{r^2} = {a^2}\cos 2\theta ,\,\,\,{r^2} = - {a^2}\cos 2\theta , \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{r^2} = {a^2}\sin 2\theta ,\,\,\,{r^2} = - {a^2}\sin 2\theta , \hfill \\ {\text{represent}}\,\,{\text{propeller - shaped}}\,\,{\text{curves}}\,\,{\text{called}}\,\,{\text{_________}}{\text{.}} \hfill \\\ \end{gathered} \]
- A) \[{\text{lemniscates}}\]
- B) \[{\text{rose }}\,\,{\text{curve}}\]
- C) \[{\text{cardioids}}\]
- D) \[{\text{spiral}}\]
{\rm{The}}\,{\rm{value}}\,{\rm{of}}\,{\rm{integral }}\int\limits_0^1 {\int\limits_0^1 {e^{x + y} dxdy} } \,\,{\rm{is}}
- A) e-1
- B) e^2-1 \over 2
- C) e^2-1 \over 4
- D) (e-1)^2
\({\rm{The}}\,{\rm{value}}\,{\rm{of}}\,{\rm{integral }}\int\limits_0^1 {\int\limits_0^1 {e^{x + y} dxdy} } \,\,{\rm{is}} \)
- A) \(e^2-1 \over 2\)
- B) \(e-1\)
- C) \((e-1)^2\)
- D) \(e^2-1 \over 4\)
\[{\text{In polar coordinates, }}\iint\limits_R {f(x,\,\,y)\,\,dx\,dy\,\, = \,\, - - - - - - }\,\]
- A) \[\iint\limits_G {f(r\,\sin \,\theta ,\,\,r\,\cos \theta )\,rdr\,d\theta }\]
- B) \[\iint\limits_G {f(r\,\cos \theta ,\,r\,\sin \,\theta )\,dr\,d\theta }\,\,\]
- C) \[\int\limits_G {f(r\,\cos \theta ,\,r\,\sin \,\theta )\,rdr\,d\theta } \]
- D) \[\iint\limits_G {f(r\,\cos \theta ,\,r\,\sin \,\theta )\,rdr\,d\theta }\,\]
$${\text{The}} \int\limits_0^1 {{e^{{y^2}}}dx} = $$
- A) $$e + 1$$
- B) $$0$$
- C) $$e - 1$$
- D) $${e^{{y^2}}}$$
\eqalign{ & {\text{Polar co - ordinates of a point are}} \left( {{\text{ - 4,}} \frac{{ - 3\pi }}{2}} \right){\text{. Which of the following is another possible polar }} \cr & {\text{co - ordinates representation of this point?}} \cr}
- A) \left( {{\text{4,}} \frac{{3\pi }}{4}} \right)
- B) \left( {{\text{4,}} \frac{{ - \pi }}{2}} \right)
- C) \left( {{\text{4,}} \frac{{ - \pi }}{3}} \right)
- D) \left( {{\text{4,}} \frac{\pi }{4}} \right)
{\text{While changing Cartesian Integral into Polar integral, we change }}x{\text{ by - - - - - - - - - and }}y{\text{ by - - - - - - - - - - - - }}{\text{.}}
- A) Sec\,\,\theta ,\,\,\,\,\,\,Co\sec \,\,\theta
- B) Sin\,\,\theta ,\,\,\,\,\,\,Cos\,\,\theta
- C) Cos\,\,\theta ,\,\,\,\,\,Sin\,\,\theta
- D) Co\sec \,\,\theta ,\,\,\,\,\,\,Sec\,\,\theta
\[The\,point\,(\,\,3,\,\,{189^0}\,\,)\,\,{\text{and the point - - - - - - - - - - - - - - }}\,{\text{are the same in polar system}}{\text{.}}\]
- A) \[(\,\,3,\,\,{99^0}\,)\]
- B) \[(\,\, - 3,\,\,{189^0}\,\,)\]
- C) \[( - 3,\,\,{279^0}\,\,)\]
- D) \[(\,\, - 3,\,\,{9^0}\,\,)\]
\[ \int\limits_0^1 {\,\int\limits_0^{\ln \,y} {x\,} } dy\,dx\,\, = \,\, - - - - - - - - - \]
- A) \[ \frac{{\ln \,y}} {2} \]
- B) \[ \frac{{\ln \,x}} {2} \]
- C) \[ \ln \,y \]
- D) \[ \frac{{\left( {\ln \,x} \right)^2 }} {2} \]
The\,value\,of\,integral\,\int\limits_0^\pi {\int\limits_0^\pi {d\theta d\varphi } } \,\,is
- A) \frac{\pi }{2}
- B) 0
- C) \pi ^2
- D) 1
$${\text{Reversing the order of integration}} \int\limits_0^2 {\int\limits_{\frac{y}{2}}^1 {{e^{{x^2}}}dxdy = } } $$
- A) $$\int\limits_0^1 {\int\limits_{\frac{y}{2}}^{4x} {{e^{{x^2}}}dydx} } $$
- B) $$\int\limits_0^1 {\int\limits_0^{{x^2}} {{e^{{x^2}}}dy} } dx$$
- C) $$\int\limits_0^1 {\int\limits_0^x {{e^{{x^2}}}dy} } dx$$
- D) $$\int\limits_0^1 {\int\limits_0^{2x} {{e^{{x^2}}}dydx} } $$
\int\limits_0^1 {\int\limits_0^1 {\int\limits_0^1 {{x^2}{y^2}{z^2}} } } \,dx\,\,dy\,\,dz = \,\,\, - - - - - - - -
- A) \frac{1}{{30}}
- B) \frac{1}{{27}}
- C) \frac{1}{9}
- D) \frac{1}{3}
\[{\text{The equation }}r = \,a\,\theta {\text{ represents - - - - - - - - - , where }}a{\text{ is positive}}{\text{.}}\]
- A) \[{\text{cardioid}}\]
- B) \[{\text{rose curve}}\]
- C) \[{\text{lemniscate}}\]
- D) \[{\text{spiral}}\]