MCQ Bank
\(The\,value\,of\,integral\,\int\limits_0^1 {\int\limits_{x^2 }^x {x\,} } dydx\,\,is \)
- A) \(0\)
- B) \(1\)
- C) \({{1} \over 12}\)
- D) \(12\)
The\,point\,(\,\,3,\,\,{189^0}\,\,)\,\,{\text{and the point - - - - - - - - - - - - - - }}\,{\text{are the same in polar system}}{\text{.}}
- A) (\,\, - 3,\,\,{189^0}\,\,)
- B) (\,\,3,\,\,{99^0}\,)
- C) (\,\, - 3,\,\,{9^0}\,\,)
- D) ( - 3,\,\,{279^0}\,\,)
$${\text{The}} \int\limits_0^1 {2x{e^{{x^2}}}dx} = $$
- A) $$e - 1$$
- B) $$e + 1$$
- C) $${e^{{x^2}}}$$
- D) $$e$$
\[{\text{In polar coordinate system, the equation }}r\, = \,a{\text{ represents a circle with center at}}\,{\text{ - - - - - - - }}{\text{.}}\]
- A) \[{\text{None of these}}{\text{.}}\]
- B) \[{\text{Origin}}\]
- C) \[x - {\text{axis}}\,\,{\text{and passes through the origin}}{\text{.}}\]
- D) \[y - {\text{axis}}\,\,{\text{and passes through the origin}}{\text{.}}\]
If the value of the integral \int_0^3 {\int_0^1 {(x + 1)dydx} } =15/2 , then what will be the value of the integral \int_0^1 {\int_0^3 {(x + 1)dxdy} }?
- A) -15/2
- B) 15/2
- C) 0
- D) 9/2
The\,value\,of\,integral\,\int\limits_0^1 {\int\limits_{x^2 }^x {x\,} } dydx\,\,is
- A) 12
- B) {{1} \over 12}
- C) 1
- D) 0
\(The\,value\,of\,integral\,\int\limits_0^4 {\int\limits_0^{\frac{1}{4}y} {5\,} } dxdy\,is \)
- A) 10
- B) 5
- C) 4
- D) 0
\({\rm{The}}\,{\rm{value}}\,{\rm{of}}\,{\rm{integral }}\int\limits_0^{\frac{\pi }{2}} {\int\limits_0^\pi {\cos (x + y)dxdy} } \,\,{\rm{is}} \)
- A) 0
- B) 2
- C) 4
- D) -2
$${{\text{In polar coordinate system, x - axis is also called}}}$$
- A) $${{\text{None of these}}}$$
- B) $${{\text{Pole}}}$$
- C) $${{\text{Imaginary axis}}}$$
- D) $${{\text{Polar axis}}}$$
\begin{gathered} {\text{If}}\,\,Pdx + Qdy + Rdw\,\,{\text{is}}\,\,{\text{an}}\,\,{\text{exact}}\,\,{\text{differential}}\,\,{\text{equation}}\,\,{\text{then}}\,\,\int\limits_C {\left( {Pdx + Qdy + Rdw} \right)\,\,{\text{is}}} {\text{_________}}\,\,{\text{of}} \hfill \\\ {\text{the}}\,\,{\text{path}}\,\,{\text{of}}\,\,{\text{integration}}\,{\text{.}} \hfill \\\\ \end{gathered}
- A) {\text{independent}}
- B) {\text{dependent}}
- C)
- D)
{\text{The arc length of the curve }}r(t) = {t^2}i - tj{\text{ }};{\text{ }}0 \leqslant t \leqslant 1{\text{, can be written as }}
- A) L = \int\limits_0^1 {\sqrt {2{t^2} - 1} } dt
- B) L = \int\limits_0^1 {\sqrt {4{t^2} - 1} } dt
- C) L = \int\limits_0^1 {\sqrt {4{t^2} + 1} } dt
- D) L = \int\limits_0^1 {\sqrt {2{t^2} + 1} } dt
\[r(t) = x(t)\,i + y(t)\,j\]
- A) is a real valued function
- B) is a vector valued function
- C)
- D)
$$\eqalign{ & {\text{Wallis sine formula when n is odd}} \cr & \int\limits_0^{\frac{\pi }{2}} {Si{n^7}xdx} = \cr} $$
- A) $$\frac{6}{7} \cdot \frac{4}{5} \cdot \frac{2}{3}$$
- B) $$\frac{7}{6} \cdot \frac{5}{4} \cdot \frac{3}{2} \cdot \frac{\pi }{2}$$
- C) $$\frac{6}{7} \cdot \frac{4}{5} \cdot \frac{2}{3} \cdot \frac{\pi }{2}$$
- D) $$\frac{7}{6} \cdot \frac{5}{4} \cdot \frac{3}{2}$$
{\text{For}}\,\,{\text{a}}\,\,{\text{function}}\,\,\vec r(t) = x(t)\hat i + y(t)\hat j + z(t)\hat k\,\,{\text{in}}\,\,{\text{3 - space}}\,\,{\text{we}}\,\,{\text{define}}\,\,\mathop {\lim }\limits_{t \to \alpha } \,\vec r(t) = \_\_\_\_\_\_\_\_\_.
- A) \left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + \left( {\mathop {\lim }\limits_{t \to \alpha } z(t)} \right)\hat k
- B) \left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j
- C) \left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + z(t)\hat k
- D) x(t)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + \left( {\mathop {\lim }\limits_{t \to \alpha } z(t)} \right)\hat k
\begin{gathered} {\text{The}}~ {\text{graph}}~ {\text{of}}~ \hfill \ {\text{r = (1 + t)}} {\text{i + ( - }} {\text{3t)}} {\text{j + }} {\text{(2 + 4t)}} {\text{k}} \hfill \ ~{\text{is}}~ {\text{the}} \hfill \\ \end{gathered}
- A) line Perpendicular to the vector {\text{ i + 2k}}
- B) line Perpendicular to the vector {\text{ i - 3j + 4k}}
- C) line parallel to the vector {\text{ i + 2k}}
- D) line parallel to the vector {\text{ i - 3j + 4k}}
\int\limits_0^{\frac{\pi }{2}} {Co{s^2}x} dx = \frac{1}{2}\left| {\frac{\pi }{2} + \frac{{\sin \pi }}{2}} \right| =
- A) \frac{{3\pi }}{4}
- B) \frac{\pi }{2}
- C) \frac{\pi }{4}
- D) \frac{\pi }{3}
The differential dz of the function \[z = {x^2} + {y^2}\] is
- A) \[dz = (2x + 2y)dz\]
- B) \[dz = 2xdx + 2ydy\]
- C) \[dz = 2dx + 2dy\]
- D) \[dz = 2x + 2y\]
$${\text{One of the line integral properties is}} \int\limits_c {Fds = } $$
- A) $$\int\limits_c {\left( {Pdx + Qdy} \right)} $$
- B) $$\int\limits_c {\left( {Pdx - Qdy} \right)} $$
- C) $$\int\limits_c {\left( {Pdy + Qdx} \right)} $$
- D) $$\int\limits_c {(P + Q)ds} $$
{\text{One of the line integral properties is}} \int\limits_{AB} {Fds = } - \int\limits_{BA} {Fds}
- A) True
- B) False
- C)
- D)
\[I = \int\limits_C {f(x,y)dx = } \int\limits_C {f(x,y)\frac{{ds}}{{dx}}dx,\,\,{\text{where}}\,\,\frac{{ds}}{{dx}} = \_\_\_\_\_\_\_\_\_.} \]
- A) \[\sqrt {1 + \frac{{dy}}{{dx}}} \]
- B) \[\sqrt {1 - {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \]
- C) \[\sqrt {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \]
- D) \[\sqrt {{{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \]