$$\eqalign{ & {\text{In 3D - space the parametric equations }}x = {\text{ }}x(t),y{\text{ }} = {\text{ }}y(t),{\text{ }}z = z(t){\text{ can be expressed in single vector }} \cr & {\text{equation as}} \cr}$$

• A) $$\vec r(t) = x(t)i + y(t)j + z(t)k$$
• B) $$\vec r(t) = x(t)j + y(t)i + z(t)k$$
• C) $$\vec r(t) = x(t) - y(t) - z(t)$$
• D) $$\vec r(t) = x(t) + y(t) + z(t)$$

$\begin{gathered} {\text{Let G be the rectangular box defined by the inequalities }}a \leqslant x \leqslant b,\,\,\,c \leqslant y \leqslant d,\,\,\,\,\,e \leqslant z \leqslant f. \hfill \ {\text{If }}f\,\,{\text{is continuous on G, then}}\,\,\int\limits_a^b {\int\limits_c^d {\int\limits_e^f {f(x,\,\,y,\,\,z)} } } \,dz\,\,dy\,\,dx = \,\,\, - - - - - - - - \hfill \\ \end{gathered}$

• A) $\int\limits_e^f {\int\limits_a^b {\int\limits_c^d {f(x,\,\,y,\,\,z)} } } \,dy\,\,dx\,\,dz$
• B) ${\text{All}}\,{\text{three}}\,{\text{options}}\,{\text{are}}\,{\text{true}}{\text{.}}$
• C) $\int\limits_c^d {\int\limits_a^b {\int\limits_e^f {f(x,\,\,y,\,\,z)} } } \,dz\,\,dx\,\,dy\,$
• D) $\int\limits_a^b {\int\limits_e^f {\int\limits_c^d {f(x,\,\,y,\,\,z)} } } \,dy\,\,dz\,\,dx$

\[{\text{The}}\,\,{\text{curve}},\,\,r = \theta \,\,(\theta \geqslant 0),\,\,{\text{is}}\,\,{\text{an}}\,\,{\text{equation}}\,\,{\text{of}}\,\,\_\_\_\_\_\_\_\_\_.\]

• A) \[{\text{cardioids}}\]
• B) \[{\text{spiral}}\,\,{\text{with}}\,\,a = 1\]
• C) \[{\text{roses}}\]
• D) \[{\text{limacons}}\]

$${\text{For a vector valued function }}\vec r(t){\text{ }} = {\text{ }}\sqrt {2t} {\text{ }}i + (t + 1){\text{ }}j{\text{ then lenght of }}\vec r(t){\text{ }}$$

• A) $$\left\| {r(t)} \right\| = \sqrt {4t + {{(t - 1)}^2}}$$
• B) $$\left\| {r(t)} \right\| = \sqrt {4{t^2} + {{(t - 1)}^2}}$$
• C) $$\left\| {r(t)} \right\| = \sqrt {2{t^2} + {{(t - 1)}^2}}$$
• D) $$\left\| {r(t)} \right\| = \sqrt {2t + {{(t - 1)}^2}}$$

$$\begin{gathered} {\text{If}}\,\,\vec r(t) = x(t)\hat i + y(t)\hat j\,\,{\text{is}}\,\,{\text{a}}\,\,{\text{vector - valued}}\,\,{\text{function}}\,\,{\text{in}}\,\,{\text{2 - space,}}\,\,{\text{and}}\,\,{\text{if}}\,\,x(t)\,\,{\text{and}}\,\,y(t)\,\,{\text{are}}\,\,{\text{differentiable,}}\,\, \hfill \\ {\text{then}}\,\,\,\frac{d}{{dt}}\,\left[ {\vec r(t)} \right] = \_\_\_\_\_\_\_\_\_. \hfill \\\ \end{gathered}$$

• A) $$x'(t)\hat i + y'(t)\hat j$$
• B) $$x'(t)\hat i + y(t)\hat j$$
• C) $$x(t)\hat i + y'(t)\hat j$$
• D) $$x'(t)\hat i + y'(t)\hat j + z'(t)\hat k$$

\[{\text{For}}\,\,{\text{a}}\,\,{\text{function}}\,\,\vec r(t) = x(t)\hat i + y(t)\hat j + z(t)\hat k\,\,{\text{in}}\,\,{\text{3 - space}}\,\,{\text{we}}\,\,{\text{define}}\,\,\mathop {\lim }\limits_{t \to \alpha } \,\vec r(t) = \_\_\_\_\_\_\_\_\_.\]

• A) \[\left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + z(t)\hat k\]
• B) \[\left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + \left( {\mathop {\lim }\limits_{t \to \alpha } z(t)} \right)\hat k\]
• C) \[x(t)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j + \left( {\mathop {\lim }\limits_{t \to \alpha } z(t)} \right)\hat k\]
• D) \[\left( {\mathop {\lim }\limits_{t \to \alpha } x(t)} \right)\hat i + \left( {\mathop {\lim }\limits_{t \to \alpha } y(t)} \right)\hat j\]

Graph of a vector-valued function can fail to have a tangent vector at a point because

• A) d) Neither a) nor b)
• B) c) Both a) and b)
• C) a) derivative does not exists at that point
• D) b) derivative is zero at that point

$\begin{gathered} {\text{Let }}\bar r(t)\,\, = \,\,2{t^2}\,\hat i\,\, + \,\,3{t^3}\,\,\hat j,\,\,{\text{then}}\,\,\bar r'(1)\,\, = \,\,4\,\hat i\,\, + \,\,9\,\hat j. \hfill \ \hfill \\ \end{gathered} $

• A) $False$
• B) $True$
• C)
• D)

$${\text{The equation }}r\, = \,a(1 + \cos \,\theta ){\text{ represents - - - - - - - - - }}{\text{.}}$$

• A) $${\text{a straight line}}$$
• B) $${\text{rose curve}}$$
• C) $${\text{lemniscate}}$$
• D) $${\text{cardioid}}$$

\[{\text{If}}\,\,\vec r(t) = 3{t^2}\hat i + 2t\,\hat j,\,\,{\text{then}}\,\,\int {\vec r(t)\,dt = \_\_\_\_\_\_\_\_\_.} \]

• A) \[{t^3}\hat i + {t^2}\,\hat j + {C_1}\hat i + {C_2}\hat j\]
• B) \[{t^3} + {t^2}\, + {C_1}\]
• C) \[{t^3}\hat i + {t^2}\,\hat j + {C_2}\hat j\]
• D) \[6t\,\hat i + 2\,\hat j\]

\[{\text{The differential equation, }}{\kern 1pt} {\kern 1pt} dz{\kern 1pt} = {\kern 1pt} 4xy{\kern 1pt} dx{\kern 1pt} {\kern 1pt} + {\kern 1pt} {\kern 1pt} \left( {2{x^2} + 3{y^2}} \right){\kern 1pt} dy,{\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\text{is}}\,\,{\kern 1pt} {\text{an exact differential equation}}{\text{.}}\]

• A) \[{\text{True}}\]
• B) \[{\text{False}}\]
• C)
• D)

$$\begin{gathered} {\text{In polar coordinate system, the equation }}r\, = \,-2a\,\sin \,\theta {\text{ represents a circle passes through the origin,}}\, \ {\text{with center on}}\,{\text{ - - - - - - - }}{\text{.}} \\ \end{gathered}$$

• A) $$x - {\text{axis,}}\,\,{\text{right to the origin}}{\text{.}}$$
• B) $$x - {\text{axis,}}\,\,{\text{left to the origin}}{\text{.}}$$
• C) $$y - {\text{axis,}}\,\,{\text{above the origin}}{\text{.}}$$
• D) $$y - {\text{axis,}}\,\,{\text{below}}\,{\text{the origin}}{\text{.}}$$

${\text{While changing Cartesian Integral into Polar integral, we change }}x{\text{ by - - - - - - - - - and }}y{\text{ by - - - - - - - - - - - - }}{\text{.}}$

• A) $Co\sec \,\,\theta ,\,\,\,\,\,\,Sec\,\,\theta$
• B) $Sin\,\,\theta ,\,\,\,\,\,\,Cos\,\,\theta$
• C) $Cos\,\,\theta ,\,\,\,\,\,Sin\,\,\theta$
• D) $Sec\,\,\theta ,\,\,\,\,\,\,Co\sec \,\,\theta$

$${\text{The}}\,\,{\text{vector}}\,\,\vec r\,\,{\text{is}}\,\,{\text{continuous}}\,\,{\text{at}}\,\,{t_0}\,\,{\text{if}}\,\,\_\_\_\_\_\_\_\_\_.$$

• A) $${\text{(d)}}\,\,\,\,\,\,{\text{All}}\,\,{\text{(a),}}\,\,{\text{(b)}}\,\,{\text{and}}\,\,{\text{(c)}}\,{\text{.}}$$
• B) $${\text{(c)}}\,\,\,\,\,\,\mathop {\lim }\limits_{t \to {t_0}} \vec r(t)\,\, = \vec r({t_0})\,.$$
• C) $${\text{(b)}}\,\,\,\,\,\,\mathop {\lim }\limits_{t \to {t_0}} \vec r(t)\,\,{\text{exist}}.$$
• D) $${\text{(a)}}\,\,\,\,\,\,\vec r({t_0})\,\,{\text{is}}\,\,{\text{defined}}.$$

$${\text{If}}\,\,\vec r(t) = 3{t^2}\hat i + 2t\,\hat j,\,\,{\text{then}}\,\,\int {\vec r(t)\,dt = \_\_\_\_\_\_\_\_\_.}$$

• A) $${t^3} + {t^2}\, + {C_1}$$
• B) $${t^3}\hat i + {t^2}\,\hat j + {C_2}\hat j$$
• C) $$6t\,\hat i + 2\,\hat j$$
• D) $${t^3}\hat i + {t^2}\,\hat j + {C_1}\hat i + {C_2}\hat j$$

$$r(t) = x(t)\,i + y(t)\,j$$

• A) is a vector valued function
• B) is a real valued function
• C)
• D)

$$\eqalign{ & {\text{The arc length of the portation of the circular helix where }}(dx/dt) = - \sin t, (dy/dt) = \cos t \cr & {\text{and}} (dz/dt) = 1 {\text{and }}0 \leqslant t \leqslant \pi {\text{, then the arc lenght is}} \cr}$$

• A) $$L = \int\limits_0^\pi {\sqrt 2 } dx$$
• B) $$L = \int\limits_0^\pi {\sqrt 2 } dy$$
• C) $$L = \int\limits_0^\pi {\sqrt 2 } dt$$
• D) $$L = \int\limits_0^\pi { - \sqrt 2 } dt$$

$$\begin{array}{l} If ~x'(t) ~and~ y'(t)~ are ~continuous, ~then~ the ~curve~ given~ by ~the ~parametric ~equation\x = x(t) , y = y(t) ~has ~arc~ length \end{array}$$

• A) $$L = \int\limits_a^b {\sqrt {{{\left( {\frac{{dx}}{{dt}}} \right)}^2} + {{\left( {\frac{{dy}}{{dt}}} \right)}^2} } } dt$$
• B) $$L = \int\limits_a^b {\sqrt {{{\left( x \right)}^2} + {{\left( y \right)}^2} } } dxdy$$
• C) $$L = \int\limits_a^b {\sqrt {\frac{{dx}}{{dt}} + \frac{{dy}}{{dt}} } } dt$$
• D) None of these

$${\text{The}}\,\,{\text{equation,}}\,\,\,{r^2} = 4\cos 2\theta ,\,\,{\text{represents}}\,\,{\text{a}}\,\,\_\_\_\_\_\_\_\_\_.$$

• A) $${\text{cardioids}}$$
• B) $${\text{rose }}\,\,{\text{curve}}$$
• C) $${\text{spiral}}$$
• D) $${\text{lemniscate}}$$

$\int\limits_0^1 {\int\limits_0^1 {\int\limits_0^1 {xyz} } } \,dx\,\,dy\,\,dz = \,\,\, - - - - - - - -$

• A) $\frac{1}{{10}}$
• B) $\frac{1}{2}$
• C) $\frac{1}{8}$
• D) $\frac{1}{4}$